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3n^2-0.75=360
We move all terms to the left:
3n^2-0.75-(360)=0
We add all the numbers together, and all the variables
3n^2-360.75=0
a = 3; b = 0; c = -360.75;
Δ = b2-4ac
Δ = 02-4·3·(-360.75)
Δ = 4329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4329}=\sqrt{9*481}=\sqrt{9}*\sqrt{481}=3\sqrt{481}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-3\sqrt{481}}{2*3}=\frac{0-3\sqrt{481}}{6} =-\frac{3\sqrt{481}}{6} =-\frac{\sqrt{481}}{2} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+3\sqrt{481}}{2*3}=\frac{0+3\sqrt{481}}{6} =\frac{3\sqrt{481}}{6} =\frac{\sqrt{481}}{2} $
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